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Tinaco: Mexican raised water tank

Mexican raised water tank

The final architectural tidbit which caught my fancy during our Mexican adventure was the raised water tanks (known in Mexico as tinacos.)  We noticed these last year during our drive through the city of Merida, and were surprised that such an archaic method of producing a household's water pressure would be found in the heart of the city.  (Not that I have anything against archaic systems --- we have a gravity feed water system much like it on our farm.)

Yucatan water systemAlthough the internet is a bit vague on the purpose of tinacos, my understanding is that cities in the Yucatan have municipal water systems, but that you can't count on them to always be operating.  Added to that, the Yucatan has frequent floods due to storms from the ocean, at which point the city water is muddy and unpotable. 

A tinaco equalizes out these problems by providing a backup supply of water for the household.  Every evening, Mexican families use the pressure of the city water to fill up their tinaco, and then water passively falls from the tank to fill their toilets, washing machines, and sinks throughout the day.  Since the most commonly used tanks hold 290 gallons, a family can easily go a day or two without hooking into the municipal system if the water is turned off or is dirty.

One article also notes that the city water may not provide enough pressure to fill your tinaco in certain locations, in which case you'll end up with an elaborate system like the one shown above.  The city water trickles into a buried cistern, then is pumped up into the tinaco as needed, a bit like self-sufficient U.S. homes might fill up a bladder tank with well water to provide pressure without running the pump continuously.  I like the low tech solution, but I wonder what their water pressure is like?

Our homemade chicken waterer solves the chicken water problem in a similarly low tech way.




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These would be useful in the U.S. for areas where the snow puts the power out for a week or so at a time.
Comment by Faith Wed Jan 12 10:53:16 2011

You need 30 feet of height to get one bar of water pressure. Looking at the height the tank sits, I'd say the pressure is not much.

Out water mains here are supposed to have two bars of pressure.

But for a tap you don't need much. It is just that with lower pressure you need bigger pipes to get the same volume flow. Just look at a typical old-fashioned toilet with the reservoir close to the ceiling. Those flush really well, using a pipe that is about an inch thick.

Comment by Roland Smith Wed Jan 12 14:28:58 2011

Faith --- That's right along the lines I was thinking. I love looking at "less developed" countries for tips on how to survive when the power goes out.

Roland --- I was looking into water pressure a month ago when Mark and I first started thinking about bladder tanks. It seemed like there's a wide range of acceptable flow rates in municipal water systems, maybe because of different pipe sizes? It seemed like our flow rate (1 gallon per minute) was in the realm of ordinary, but at the low end. Can you do a quick conversion for me and tell me what flow rate you'd get at 1 bar of pressure with one inch pipe?

Comment by anna Thu Jan 13 10:02:56 2011

Warning: Maths ahead :-)

Assuming laminar flow for the moment, according to the Hagen-Poiseulle equation (only valid for laminar flow!), volume flow is:

Q = ΔP·π·d⁴/(128·μ·L)

For laminar flow, the Reynolds number should be <2300;

Re = Q·L/(ν·A)

where

  • Q: volume flow in m³/s
  • ΔP: pressure difference in Pa (1 bar = 10⁵ Pa)
  • d: pipe diameter in m (1 in = 0.0254 m)
  • μ: dynamic viscosity in Pa·s (10⁻³ Pa·s for water @ 293 K)
  • ν: kinematic viscosity in m²/s (10⁻⁶ m²/s for water @ 293 K)
  • L: pipe length in m.
  • A: pipe cross-sectional area in m² (0.00051 m² for 1 inch pipe)

For 30 meters (100 feet) of pipe, this gives 0.034 m³/s (9 gallons/second).

Now we need to check our assumptions! With this flow, the Reynolds number is 2·10⁹. So in this situation there will not be a laminar flow, and the above calculation is invalid.

So now you need to use the Darcy-Weisbach equation to determine the volume flow. This is where it gets complicated. For this calculation you will need to know something about the roughness of the inside of the pipe, to get at the Darcy friction factor, which depends on the Reynolds number, which depends on the volume flow. :-/ Calculation now becomes an iterative process.

You can use this online calculator to play with the numbers. For a 30 m long 1 inch pipe, you'd get around 0.0015 m³/s (0.4 gallon/s) for a 1 bar pressure loss (assuming a friction factor of 0.019).

Here in the Netherlands, water pipes in homes are typically 10 mm inner diameter. For the same length of pipe and pressure, that would yield 0.00015 m³/s (0.04 gallons/second).

Comment by Roland Smith Thu Jan 13 17:09:47 2011
If your final prediction is right, that gives a flow rate of 2.4 gallons per minute, which is actually quite good. Since I suspect pipe lengths would be less than 100 feet, it sounds like the tinacos might have our system beat... :-)
Comment by anna Thu Jan 13 20:02:09 2011

Keep in mind that bends in the pipes (especially right angles) can have as much resistance as several yards of pipe (depending on flow rate, diameter etc.)

For pumping water from the creek, you might want to look at a hydraulic ram as an alternative to an electric motor driven pump. It can use the kinetic energy of flowing water to pump water up. It's main benefit is it's simplicity; it has only two moving parts, and can be made from very basic materials.

Comment by Roland Smith Fri Jan 14 15:45:56 2011
We've looked into hydraulic rams several times, and I always have to re-look the information up to see why it won't work for us. The first deterrent is the price tag --- even building your own, it looks like you need to spend at least $100 on parts. But more important is the elevation issue. You have to have at least 5 feet of elevation drop between the inlet and the pump, and our creek is flat as a pancake. The same problem that bogs down all of our hydroelectric dreams...
Comment by anna Sat Jan 15 18:51:43 2011
I have recently build a permanent house in a rural set up where i grew up.My bigger dream is to have an efficient rain water collecting system that would solve water shortage problem we have faced all a long.i have already purchased two KENTANK( heavy plastic tanks) and intend to put one below the level ground so all the the water from the gathers drain into it and subsequently with the use of a small pedrollo horse pump powered with electricity,water is pumped to a tank raised six meters above the ground.once up supply to the internal toilet and bathroom should by gravity I need advise on how to do it nicely to cover efficiency,reinforcement,durability,capacity and aesthetics address pmutaiya@yahoo.com country Kenya East Africa home town Kericho
Comment by Peter mutai Sun Jan 30 09:41:04 2011
I'd love to help you out, Peter, but I'm far from an expert. That said, I (and our readers) could probably give you better advice if you ask a more specific question. What exactly are you most stumped by?
Comment by anna Wed Feb 2 11:37:38 2011
Thanks Anna for the concern,I would ask four quiz(1)what material if used would provide a strong and durable support for the raised water tank fully loaded say 40,000.00 litres? (2)which pipes,plastic or metallic? How about the pipe internal diameter? (3)I need a skeleton structural design to guide the laying down of the pipes to inlude angles n connections at junction points(4)In seasons where rain is erratic,I would like the system to support watering an adjacent green house with tomatoes and other horticultural crops,but how? Kindly send in your advice,photos of the house is available on request.Thanks pmutaiya@yahoo.com
Comment by Peter Mutai Sun Feb 6 07:47:07 2011



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